Delete Node in a BST Solutions in Python

"""
case 1: if node we want to delete has no children: simply delete it
case 2: if it has only one child, then replace it with its child
case 3: if it has two children, first find the inorder successor (or predecessor),
        then replace the node's value with successor's value, and finally delete this successor
"""

def deleteNode(self, root, key):
    if not root: return None
    if key < root.val: 
        root.left = self.deleteNode(root.left, key)
    elif key > root.val:
        root.right = self.deleteNode(root.right, key)
    else:
        # if this node has only one child or no child:
        if not root.left:
            temp = root.right
            root = None
            return temp
        elif not root.right:
            temp = root.left
            root = None
            return temp
        
        # otherwise, find the inorder successor:
        curr = root.right
        while curr.left:
            curr = curr.left
        
        root.val = curr.val
        root.right = self.deleteNode(root.right, curr.val)
    return root