Flatten Binary Tree to Linked List Solutions in Go

package leetcode

import (
	"github.com/halfrost/LeetCode-Go/structures"
)

// TreeNode define
type TreeNode = structures.TreeNode

/**
 * Definition for a binary tree node.
 * type TreeNode struct {
 *     Val int
 *     Left *TreeNode
 *     Right *TreeNode
 * }
 */

// 解法一 非递归
func flatten(root *TreeNode) {
	list, cur := []int{}, &TreeNode{}
	preorder(root, &list)
	cur = root
	for i := 1; i < len(list); i++ {
		cur.Left = nil
		cur.Right = &TreeNode{Val: list[i], Left: nil, Right: nil}
		cur = cur.Right
	}
	return
}

func preorder(root *TreeNode, output *[]int) {
	if root != nil {
		*output = append(*output, root.Val)
		preorder(root.Left, output)
		preorder(root.Right, output)
	}
}

// 解法二 递归
func flatten1(root *TreeNode) {
	if root == nil || (root.Left == nil && root.Right == nil) {
		return
	}
	flatten(root.Left)
	flatten(root.Right)
	currRight := root.Right
	root.Right = root.Left
	root.Left = nil
	for root.Right != nil {
		root = root.Right
	}
	root.Right = currRight
}

// 解法三 递归
func flatten2(root *TreeNode) {
	if root == nil {
		return
	}
	flatten(root.Right)
	if root.Left == nil {
		return
	}
	flatten(root.Left)
	p := root.Left
	for p.Right != nil {
		p = p.Right
	}
	p.Right = root.Right
	root.Right = root.Left
	root.Left = nil
}