Number of Boomerangs Solutions in C++

/// Source : https://leetcode.com/problems/number-of-boomerangs/description/
/// Author : liuyubobobo
/// Time   : 2017-11-15

#include <iostream>
#include <vector>
#include <unordered_map>
#include <cassert>
#include <stdexcept>

using namespace std;

/// Using Hash Map
/// Time Complexity: O(n^2)
/// Space Complexity: O(n)
class Solution {
public:
    int numberOfBoomerangs(vector<vector<int>>& points) {

        int res = 0;
        for( int i = 0 ; i < points.size() ; i ++ ){

            // record中存储 点i 到所有其他点的距离出现的频次
            unordered_map<int, int> record;
            for(int j = 0 ; j < points.size() ; j ++)
                if(j != i)
                    // 计算距离时不进行开根运算, 以保证精度
                    record[dis(points[i], points[j])] += 1;

            for(unordered_map<int, int>::iterator iter = record.begin() ; iter != record.end() ; iter ++)
                res += (iter->second) * (iter->second - 1);
        }
        return res;
    }

private:
    int dis(const vector<int> &pa, const vector<int> &pb){
        return (pa[0] - pb[0]) * (pa[0] - pb[0]) +
               (pa[1] - pb[1]) * (pa[1] - pb[1]);
    }
};


int main() {

    vector<pair<int,int>> vec;
    vec.push_back(make_pair(0, 0));
    vec.push_back(make_pair(1, 0));
    vec.push_back(make_pair(2, 0));

    cout << Solution().numberOfBoomerangs(vec) << endl;

    return 0;
}